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4n^2-17n=0
a = 4; b = -17; c = 0;
Δ = b2-4ac
Δ = -172-4·4·0
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-17}{2*4}=\frac{0}{8} =0 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+17}{2*4}=\frac{34}{8} =4+1/4 $
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